#Scrambled word solver 2 words code
#Scrambled word solver 2 words plus
#Scrambled word solver 2 words series

The contestant then unscrambles the circled letters to form the answer to the clue. In order to find the letters that are in the answer to the given clue, the player must unscramble all four of the scrambled words the letters that are in the clue will be circled.

#Scrambled word solver 2 words plus

A weekly 'kids version' of the puzzle features a three-letter word plus three four-letter words. The answer to the clue is generally a pun of some sort.

#Scrambled word solver 2 words series

The current syndicated version found in most daily newspapers (under the official title Jumble-That Scrambled Word Game) has four base anagrams, two of five letters and two of six, followed by a clue and a series of blank spaces into which the answer to the clue fits. Daily and Sunday Jumble puzzles appear in over 600 newspapers in the United States and internationally. Jumble is one of the most valuable properties of its distributor, US company Tribune Content Agency, which owns the JUMBLE trademarks and copyrights. As of 2013, Jumble was being maintained by David L. It originally appeared under the title 'Scramble.' Henri Arnold and Bob Lee took over the feature in 1962 and continued it for at least 30 years. Jumble was created in 1954 by Martin Naydel, who was better known for his work on comic books. The answer phrase frequently uses a homophone or pun. The clue and illustration always provide hints about the answer phrase. A solver reconstructs the words, and then arranges letters at marked positions in the words to spell the answer phrase to the clue. Pretty much along the same lines as above, sort the characters within the string for both source and target strings.Jumble is a word puzzle with a clue, a drawing illustrating the clue, and a set of words, each of which is “jumbled” by scrambling its letters. After computing these arrays for the source (scrambled) and the target (a possible match) compare the keys and values in your associative array. Before computing this, compare lengths, if the strings are of different lengths, then don't bother comparing as you know they mismatch. If building a dictionary up front is not viable, then use a variation on this where you create an associative array/dictionary with the letter as the key, and the count of the times it's found as the value.

Output the collection referred to by the key. Perform the same hash algorithm on the scrambled word, and look up the key. Append each word with the same key to the end of the collection for that key. Use the hashed value as a key in a key-value pair, and have a collection as the value. Few, if any, words have 9 repetitions of a single letter, so a single 'digit' per letter should work fine. To cheat a little you can store the results as a a pair of strings. A is in the first array position/index 0 Z in 26th/index 25) Each position will the count of the times a specific character for that position was encountered. so you have only characters A-Z.įor each word in your dictionary, build a 'hash' based on the counts of each letters occurrence. what English is written in), everything is case insensitive and you use no numerals.etc. I am assuming you're only using the Latin alphabet (i.e. However, you should only build the dictionary once and load it! Recomputing every time is a waste of time. Constructing the initial lookup data will be slow, but finding a match should be simple. Var word = 'iexospensr' // The word I want to unscramble. var theList // Contains all the words in the English dictionary.

#Scrambled word solver 2 words code

Initially, I thought that the following code would do the trick, but it doesn't work so well. I have a scrambled word word that I want to unscramble by matching against the word list. I have a list of all the words in the English dictionary (270,000+ words) stored in a variable called theList.